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  1. Question #67e72 + Example - Socratic

    Ionic compounds do not actually satisfy the octet rule. The octet rule is that atoms of elements are most stable when the valence shell of s^2 and p^6 are filled with eight electrons, making the …

  2. Question #acdf3 - Socratic

    The balanced equation is: 4NH_(3(g))+7O_(2(g))rarr4NO_(2(g))+6H_2O_((g)) Addendum: Yes, oxygen must have a subscript of two beacause it forms diatomic molecules. There are seven …

  3. Question #6ecfc - Socratic

    The same approach is valid in this case as well, which means that DeltaH_f^ (0) (H_2O) = DeltaH_ ("rxn 2") = "-285.8 kJ/mol" So, you know the enthalpy of formation for 1 mole of …

  4. Question #d237f + Example - Socratic

    I'd say 99. In fact, a periodic number like 0.abcabcabc... is given by the fraction {abc}/999, and in general such periodic numbers are given by the fraction with the repeating block at the …

  5. Question #c7952 - Socratic

    44.009 "amu" To calculate the mass of one individual molecule of "CO"_2, we need to Multiply the atomic mass of carbon by however many carbon atoms are in the compound (1) Multiply the …

  6. Question #e4dfd - Socratic

    Each element has their own charge, based on the periodic table When we talk about elements, we really want to know what an atom is. We normally think of electrons on the outside and a …

  7. Question #61f2a - Socratic

    Feb 18, 2018 · The functional theories of grammar are different approaches to the study of language and its elements to understand linguistic structures and processes. With these …

  8. Question #7c97b - Socratic

    Since electrons have like 1/1837 the mass of a proton/neutron, we usually don't have to consider them. So, the total mass of an element is mainly the sum of the protons and neutrons. You can …

  9. Answers created by Hammer - Socratic

    Q&A and Videos that make learning easy. Math, History, Chemistry, Algebra, Calculus, Biology and more.

  10. Question #2d57f - Socratic

    The function f (x) = sin (e^x) is defined and continuous in all of RR, so that for any x_0: lim_ (x->x_0) f (x) = f (x_0) and in particular for x_k = ln (kpi) with k in NN: lim_ (x->x_k) f (x) = f (x_k) …