Jan 1, 2018 · Further, $991$ and $997$ are below $1000$ so shouldn't have been removed either. This gives $224+2+2=228$ numbers relatively prime to $210$, so $1000-228=772$ numbers are divisible …

Jul 17, 2019 · I understand that changing the divisor multiplies the result by that, but why doesn't changing the numerator cancel that out? I found out somewhere else since posting, is there a way to …

May 13, 2014 · 1 the number of factor 2's between 1-1000 is more than 5's.so u must count the number of 5's that exist between 1-1000.can u continue?

Jun 27, 2018 · A big part of this problem is that the "1 in 1000" event can happen multiple times within our attempt. Compare this to if you have a special deck of playing cards with 1000 cards in it, exactly …

I would like to find all the expressions that can be created using nothing but arithmetic operators, exactly eight $8$'s, and parentheses. Here are the seven solutions I've found (on the Internet)...

Jan 30, 2017 · Given that there are $168$ primes below $1000$. Then the sum of all primes below 1000 is (a) $11555$ (b) $76127$ (c) $57298$ (d) $81722$ My attempt to solve it: We know that below …

Oct 3, 2023 · The number of bacteria in a culture is 1000 and this number increases by 250% every two hours. How many bacteria is present after 24 hours?

May 28, 2022 · What does the sum of all the numerals from the numbers from $100$ up to $1000$ equal to?

Aug 5, 2019 · $1000$ is the number of small cubes in the original cube. Each face of the original cube contains $10\times10=100$ small cubes, so the effect of removing the small cubes on all six faces, …

Mar 1, 2018 · My task requires to find all numbers from $1-1000$ such that they are divisible by $2$ or $3$ and no other primes. I know that $2$ divides even numbers and I can use the formula $\left …